2[k-(3k+17)+11]=2(k+6)

Solution for 2[k-(3k+17)+11]=2(k+6) equation:

Simplifying
2[k + -1(3k + 17) + 11] = 2(k + 6)

Reorder the terms:
2[k + -1(17 + 3k) + 11] = 2(k + 6)
2[k + (17 * -1 + 3k * -1) + 11] = 2(k + 6)
2[k + (-17 + -3k) + 11] = 2(k + 6)

Reorder the terms:
2[-17 + 11 + k + -3k] = 2(k + 6)

Combine like terms: -17 + 11 = -6
2[-6 + k + -3k] = 2(k + 6)

Combine like terms: k + -3k = -2k
2[-6 + -2k] = 2(k + 6)
[-6 * 2 + -2k * 2] = 2(k + 6)
[-12 + -4k] = 2(k + 6)

Reorder the terms:
-12 + -4k = 2(6 + k)
-12 + -4k = (6 * 2 + k * 2)
-12 + -4k = (12 + 2k)

Solving
-12 + -4k = 12 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-12 + -4k + -2k = 12 + 2k + -2k

Combine like terms: -4k + -2k = -6k
-12 + -6k = 12 + 2k + -2k

Combine like terms: 2k + -2k = 0
-12 + -6k = 12 + 0
-12 + -6k = 12

Add '12' to each side of the equation.
-12 + 12 + -6k = 12 + 12

Combine like terms: -12 + 12 = 0
0 + -6k = 12 + 12
-6k = 12 + 12

Combine like terms: 12 + 12 = 24
-6k = 24

Divide each side by '-6'.
k = -4

Simplifying
k = -4